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5/2x^2=250
We move all terms to the left:
5/2x^2-(250)=0
Domain of the equation: 2x^2!=0We multiply all the terms by the denominator
x^2!=0/2
x^2!=√0
x!=0
x∈R
-250*2x^2+5=0
Wy multiply elements
-500x^2+5=0
a = -500; b = 0; c = +5;
Δ = b2-4ac
Δ = 02-4·(-500)·5
Δ = 10000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{10000}=100$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-100}{2*-500}=\frac{-100}{-1000} =1/10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+100}{2*-500}=\frac{100}{-1000} =-1/10 $
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